Skip to main content

ASP.NET MVC View to Controller Operation

ASP.NET MVC View to Controller  Operation:- 


 We can pass View Data (Html form or razor form elements ) using Four different ways


1)    using FormCollection:-      


 FormCollection is a predefined class that is used to store data using dictionary pattern means key=>value pair, the key will be HTML form element name, and value will be data of HTML form element.

Step for FormCollection Object:-

1)   Create Controller and define two different method 

      First Load Method or GET Method:-
   
      public ActionResult Index()
      {
           return View()
      }


      Action Method  or POST Method

      [HttpPost]
     public ActionResult Index(FormCollection obj)
      {
           return View()
      }



   Create View on right-click on Getting method:-  it will create index.cshtml

    Write following code

   @{
    Layout = null;
}

<!DOCTYPE html>

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>Index</title>
</head>
<body>
    <div>
      <form  method="post">
          <input type="text" name="txtp" placeholder="Enter P" />
          <br />
          <br />
          <input type="text" name="txtr" placeholder="Enter Rate" />
          <br />
          <br />
          <input type="text" name="txtt" placeholder="Enter Time" />
          <br />
          <br />
          <input type="submit" name="btnsubmit" value="Click" />
      </form>
        @ViewBag.Data 
    </div>
</body>
</html>


modify the code of Action Method:-

 [HttpPost]
        public ActionResult Index(FormCollection obj)
        {
            float si = float.Parse(obj["txtp"].ToString())*float.Parse(obj["txtr"].ToString())*float.Parse(obj["txtt"].ToString())/100;
            ViewBag.Data = "result is " + si;
            return View();
        }



2)    using RequestObject :-  

Request Object is the reference of HttpRequest class, It will directly get data from the request object and assign it into a variable, if we want to provide a different action method name for HttpGet and HttpPost then we can prefer Request Object.

      Create Controller with Two different methods for HttpGet and HttpPost:-
 
      public ActionResult Index()
        {
            return View();
        }

         [HttpPost]
         public ActionResult SwapCode()   //using Request 
         {
           
             return View();

         }

        Create a view on right-click on GET method and write following code:-
       @{
    Layout = null;
}

<!DOCTYPE html>

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>Index</title>
</head>
<body>
    <div>
     <form action="swap/SwapCode" method="post">
         <input type="text" name="txtnum1" placeholder="Enter First Number" />
         <br />
         <br />
         <input type="text" name="txtnum2" placeholder="Enter second number" />
         <br />
         <br />
         <input type="submit" name="btnsubmit" value="Click" />
     </form> 
    </div>
</body>
</html>


Modify Action Method Code:-

         [HttpPost]
         public ActionResult SwapCode()   //using Request 
         {
             int a = int.Parse(Request["txtnum1"]);
             int b = int.Parse(Request["txtnum2"]);
             a = a + b;
             b = a - b;
             a = a - b;
             ViewBag.data = "a=" + a + "b=" + b;
             return View();
         }


3)  using Parameters:-  

 We can create parametrized  Action Method which will receive data of Form Element using Element name.

Step for using Parameters:-

Create Load Action Method:-

 public ActionResult Index()
        {
            return View();
        }

  [HttpPost]
        public ActionResult SwapCode()   //using Request
        {
       
            return View();
        }

      Create view on right click on Get method
     @{
    Layout = null;
}

<!DOCTYPE html>

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>Index</title>
</head>
<body>
    <div>
     <form action="swap/SwapCode" method="post">
         <input type="text" name="txtnum1" placeholder="Enter First Number" />
         <br />
         <br />
         <input type="text" name="txtnum2" placeholder="Enter second number" />
         <br />
         <br />
         <input type="submit" name="btnsubmit" value="Click" />
     </form> 
    </div>
</body>
</html>
  
modify code of Action Method:-
[HttpPost]
        public ActionResult SwapCode(String txtnum1,String txtnum2)   //using Request 
        {
            int a = int.Parse(txtnum1);
            int b = int.Parse(txtnum2);
            a = a + b;
            b = a - b;
            a = a - b;
            ViewBag.data = "a=" + a + "<br>b=" + b;
            return View();
        }


4)   using Model Object or MVC Approach:-

It provides an MVC Design pattern we create model class according to form requirement. The model class will be bind by view using a strongly typed view object pattern.

Create two different methods in the controller for Get and POST, Create Model Object as a parameter in the POST method, and define code.

Controller Object will load dynamic view and get data of view under action method.

Step for Model Object:-

1) Create Controller with HttpGet method

   public class SIController: Controller
    {
        //
        // GET: /SI/

        public ActionResult Index()
        {
            return View();
        }
   

    }

2)  Create Model Class using right-click on Model Folder

   using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;

namespace BasicMVCExample.Models
{
    public class SICalc
    {
        public float P { get; set; }
        public float R { get; set; }
        public float T { get; set; }
    }
}

3)  Create Action Method under Controller then create Strongly typed view on right-click on Action Method using Template Create Option

        [HttpPost]
         public ActionResult Index(SICalc obj)
        {
         
            return View();
        }


4) Right-click on Get method and add Model Object under view. 
Automatic generated View by Create Template It is called Strongly typed view:-

@model BasicMVCExample.Models.SICalc

@{
    Layout = null;
}

<!DOCTYPE html>

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>Index</title>
</head>
<body>
    @using (Html.BeginForm()) {
        @Html.ValidationSummary(true)
 
        <fieldset>
            <legend>SICalc</legend>
 
            <div class="editor-label">
                @Html.LabelFor(model => model.P)
            </div>
            <div class="editor-field">
                @Html.EditorFor(model => model.P)
                @Html.ValidationMessageFor(model => model.P)
            </div>
 
            <div class="editor-label">
                @Html.LabelFor(model => model.R)
            </div>
            <div class="editor-field">
                @Html.EditorFor(model => model.R)
                @Html.ValidationMessageFor(model => model.R)
            </div>
 
            <div class="editor-label">
                @Html.LabelFor(model => model.T)
            </div>
            <div class="editor-field">
                @Html.EditorFor(model => model.T)
                @Html.ValidationMessageFor(model => model.T)
            </div>
 
            <p>
                <input type="submit" value="Create" />
            </p>
        </fieldset>
    }
 
    <div>
     @ViewBag.result
    </div>
</body>
</html>

     


5)  Modify Action Method Code and Write program
      [HttpPost]
         public ActionResult Index(SICalc obj)
        {
            ViewBag.result = (obj.P * obj.R * obj.T) / 100;
            return View();
        }









Labels:

Comments

Post a Comment

POST Answer of Questions and ASK to Doubt

Popular posts from this blog

Uncontrolled form input in React-JS

  Uncontrolled form input in React-JS? If we want to take input from users without any separate event handling then we can uncontrolled the data binding technique. The uncontrolled input is similar to the traditional HTML form inputs. The DOM itself handles the form data. Here, the HTML elements maintain their own state that will be updated when the input value changes. To write an uncontrolled component, you need to use a ref to get form values from the DOM. In other words, there is no need to write an event handler for every state update. You can use a ref to access the input field value of the form from the DOM. Example of Uncontrolled Form Input:- import React from "react" ; export class Info extends React . Component {     constructor ( props )     {         super ( props );         this . fun = this . fun . bind ( this ); //event method binding         this . input = React . createRef ();...
Post a Comment
Read more

JDBC using JSP and Servlet

JDBC means Java Database Connectivity ,It is intermediates from Application to database. JDBC has different type of divers and provides to communicate from database server. JDBC contain four different type of approach to communicate with Database Type 1:- JDBC-ODBC Driver Type2:- JDBC Vendor specific Type3 :- JDBC Network Specific Type4:- JDBC Client-Server based Driver  or JAVA thin driver:- Mostly we prefer Type 4 type of Driver to communicate with database server. Step for JDBC:- 1  Create Database using MYSQL ,ORACLE ,MS-SQL or any other database 2   Create Table using database server 3   Create Form according to database table 4  Submit Form and get form data into servlet 5  write JDBC Code:-     5.1)   import package    import java.sql.*     5.2)  Add JDBC Driver according to database ide tools     5.3)  call driver in program         ...
4 comments
Read more

JSP Page design using Internal CSS

  JSP is used to design the user interface of an application, CSS is used to provide set of properties. Jsp provide proper page template to create user interface of dynamic web application. We can write CSS using three different ways 1)  inline CSS:-   we will write CSS tag under HTML elements <div style="width:200px; height:100px; background-color:green;"></div> 2)  Internal CSS:-  we will write CSS under <style> block. <style type="text/css"> #abc { width:200px;  height:100px;  background-color:green; } </style> <div id="abc"></div> 3) External CSS:-  we will write CSS to create a separate file and link it into HTML Web pages. create a separate file and named it style.css #abc { width:200px;  height:100px;  background-color:green; } go into Jsp page and link style.css <link href="style.css"  type="text/css" rel="stylesheet"   /> <div id="abc"> </div> Exam...
Post a Comment
Read more